If a solution has an osmotic pressure of 0.82 | vedclass

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Question

(A) The osmotic pressure $(\pi)$ is given by the formula: $\pi = CRT$. Here,$\pi = 0.82 \ bar$,$T = 27 \ ^oC = 27 + 273 = 300 \ K$,and the gas constan

Vedclass · Accepted Answer

$0.033$

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(A) The osmotic pressure $(\pi)$ is given by the formula: $\pi = CRT$. Here,$\pi = 0.82 \ bar$,$T = 27 \ ^oC = 27 + 273 = 300 \ K$,and the gas constant $R = 0.08314 \ L \ bar \ K^{-1} \ mol^{-1}$. Rearranging the formula for concentration $(C)$: $C = \frac{\pi}{RT}$. Substituting the values: $C = \frac{0.82}{0.08314 	imes 300}$. $C = \frac{0.82}{24.942} \approx 0.033 \ M$. Therefore,the concentration is $0.033 \ M$.

If a solution has an osmotic pressure of $0.82 \ bar$ at $27 \ ^oC$,find the concentration of such a solution. (in $M$)

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