If the A.M. between p^{th} and q^{th} terms o | vedclass

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(D) Given that the $A.M.$ of the $p^{th}$ and $q^{th}$ terms is equal to the $A.M.$ of the $r^{th}$ and $s^{th}$ terms of an $A.P.$:$\frac{a_p + a_q}{

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$r + s$

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(D) Given that the $A.M.$ of the $p^{th}$ and $q^{th}$ terms is equal to the $A.M.$ of the $r^{th}$ and $s^{th}$ terms of an $A.P.$:$\frac{a_p + a_q}{2} = \frac{a_r + a_s}{2}$Using the formula for the $n^{th}$ term of an $A.P.$,$a_n = a + (n-1)d$:$a + (p-1)d + a + (q-1)d = a + (r-1)d + a + (s-1)d$Simplifying the equation:$2a + (p + q - 2)d = 2a + (r + s - 2)d$Subtracting $2a$ from both sides:$(p + q - 2)d = (r + s - 2)d$Assuming $d 
eq 0$,we can divide by $d$:$p + q - 2 = r + s - 2$Therefore:$p + q = r + s$

If the $A.M.$ between $p^{th}$ and $q^{th}$ terms of an $A.P.$ is equal to the $A.M.$ between $r^{th}$ and $s^{th}$ terms of the same $A.P.$,then $p + q$ is equal to

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