(C) The ionization potential $(IP)$ decreases as we move down a group in the periodic table due to an increase in atomic size and shielding effect.Sin

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(C) The ionization potential $(IP)$ decreases as we move down a group in the periodic table due to an increase in atomic size and shielding effect.Since $K$ is below $Na$ in Group $1$,its $IP$ must be lower than that of $Na$ $(5.48 \, eV)$.Among the given options,$4.34 \, eV$ is the only value less than $5.48 \, eV$.