If the HCF(a, b) = 16, then which of the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The fundamental property of $HCF$ and $LCM$ of two numbers $a$ and $b$ is that the $LCM$ must be perfectly divisible by the $HCF$.In other words,

Vedclass · Accepted Answer

$72$

Vedclass · Answer

(B) The fundamental property of $HCF$ and $LCM$ of two numbers $a$ and $b$ is that the $LCM$ must be perfectly divisible by the $HCF$.In other words, $\frac{LCM(a, b)}{HCF(a, b)} = 	ext{integer}$.Given $HCF(a, b) = 16$.We check each option:$1$. For $32$: $\frac{32}{16} = 2$ (Possible).$2$. For $72$: $\frac{72}{16} = 4.5$ (Not an integer, hence impossible).$3$. For $64$: $\frac{64}{16} = 4$ (Possible).Therefore, $72$ cannot be the $LCM$.

If the $HCF(a, b) = 16$, then which of the following cannot be the $LCM(a, b)$? (Options: $32, 72, 64$)

Similar Questions

The degree of the polynomial $(x+1)(x^2 - x - x^4 + 1)$ is . . . . . . .

The decimal expansion of $\frac{18}{5^{3}}$ will terminate after how many decimal places?

How many decimal places are there in the decimal expansion of $\frac{3}{113}$?

The decimal representation of $35457 / 6250$ terminates after how many decimal places?

If $m$ and $n$ are distinct prime integers,then their $HCF$ is .......... .

Vedclass Test Series

Exam Paper Generator

Online Exam Module