If the acceleration of the particle is constant in magnitude but not in direction,what type of path does the particle follow?

$A$ body thrown in the vertically upward direction rises up to a height $h$ and comes back to the position of its start. Calculate: $(a)$ the total distance travelled by the body and $(b)$ the displacement of the body. Under what condition will the magnitude of the displacement be equal to the distance travelled by an object?

What conclusion can you draw from the displacement$-$time graph of a body shown below?

The area under a $v-t$ graph represents a physical quantity which has the unit:

Differentiate between distance and displacement.

$A$ body is thrown vertically upward with velocity $u$,the greatest height $h$ to which it will rise is,