If the ammeter in the given circuit reads 2, | vedclass

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(A) The circuit consists of two resistors of $3\,\,\Omega$ and $6\,\,\Omega$ connected in parallel,which are then connected in series with a resistor

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$1\,\,\Omega$

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(A) The circuit consists of two resistors of $3\,\,\Omega$ and $6\,\,\Omega$ connected in parallel,which are then connected in series with a resistor $R$ and a $6\,V$ battery.First,calculate the equivalent resistance of the parallel combination of $3\,\,\Omega$ and $6\,\,\Omega$ resistors:$R_p = \frac{3 	imes 6}{3 + 6} = \frac{18}{9} = 2\,\,\Omega$.The total resistance of the circuit is $R_{eq} = R_p + R = 2 + R$.According to Ohm's Law,$V = I 	imes R_{eq}$.Given $V = 6\,V$ and $I = 2\,A$,we have:$6 = 2 	imes (2 + R)$$3 = 2 + R$$R = 3 - 2 = 1\,\,\Omega$.Therefore,the resistance $R$ is $1\,\,\Omega$.

If the ammeter in the given circuit reads $2\, A$,the resistance $R$ is ............ $\Omega$.

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