(D) The period $T$ of a simple harmonic motion is given by $T = 2\pi \sqrt{\frac{m}{k}}$,which shows that the period is independent of the amplitude $

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its period will not change but total energy will decrease

(D) The period $T$ of a simple harmonic motion is given by $T = 2\pi \sqrt{\frac{m}{k}}$,which shows that the period is independent of the amplitude $A$.Therefore,the period will not change.The total energy $E$ of a particle in $S.H.M.$ is given by $E = \frac{1}{2} m \omega^2 A^2$.Since $E \propto A^2$,if the amplitude $A$ is decreased,the total energy $E$ will also decrease.Thus,the period remains constant while the total energy decreases.

Class 11 Physics Oscillations Energy of Simple Harmonic Motion

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If the amplitude of linear $S.H.M.$ is decreased,then:

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A
its period and total energy will increase
B
its period will increase,and total energy will decrease
C
its period and total energy will decrease
D
its period will not change but total energy will decrease

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Oscillations

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If the amplitude of linear $S.H.M.$ is decreased,then:

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An object executes $SHM$ along the $x$-axis with an amplitude of $0.06 \,m$. At a certain distance '$x$' metres from the mean position,it has a kinetic energy of $10 \,J$ and a potential energy of $8 \,J$. The distance '$x$' will be: (in $\,m$)

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