If the angle $\theta$ between the line $\frac{x + 1}{1} = \frac{y - 1}{2} = \frac{z - 2}{2}$ and the plane $2x - y + \sqrt{\lambda} z + 4 = 0$ is such that $\sin \theta = \frac{1}{3}$,the value of $\lambda$ is

  • A
    $\frac{3}{4}$
  • B
    $-\frac{4}{3}$
  • C
    $\frac{5}{3}$
  • D
    $-\frac{3}{5}$

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