If the atomic weight of an element is 23 time | vedclass

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(C) The lightest element is hydrogen,which has an atomic weight of approximately $1$. Given that the atomic weight of the element is $23$ times that o

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$11$ protons,$12$ neutrons,$11$ electrons

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(C) The lightest element is hydrogen,which has an atomic weight of approximately $1$. Given that the atomic weight of the element is $23$ times that of hydrogen,its mass number $(A)$ is $23$. The number of protons $(Z)$ is given as $11$. Since the mass number is the sum of protons and neutrons $(A = Z + N)$,we have $23 = 11 + N$,which gives $N = 12$ neutrons. For a neutral atom,the number of electrons is equal to the number of protons,so there are $11$ electrons. Thus,the element contains $11$ protons,$12$ neutrons,and $11$ electrons.

If the atomic weight of an element is $23$ times that of the lightest element and it has $11$ protons,then it contains

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