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(A) The actual average life of a human is approximately $70$ years,which is about $2.2 	imes 10^9 \, s$. For the purpose of order of magnitude,we tak

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$10^{10}$

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(A) The actual average life of a human is approximately $70$ years,which is about $2.2 	imes 10^9 \, s$. For the purpose of order of magnitude,we take it as $10^9 \, s$.The actual age of the universe is approximately $13.8$ billion years,which is about $4.35 	imes 10^{17} \, s$. For the purpose of order of magnitude,we take it as $10^{17} \, s$.Let the scale factor be $k$. According to the problem,the human life on this scale is $100 \, s$.Therefore,$k 	imes (10^9 \, s) = 100 \, s$,which gives $k = 10^{-7}$.Now,the age of the universe on this scale is $k 	imes (10^{17} \, s) = 10^{-7} 	imes 10^{17} \, s = 10^{10} \, s$.

If the average life of a person is taken as $100 \, s$,the age of the universe on this scale is of the order of ...... $s$.

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