If the breaking strength of a rope is $\frac{4}{3}$ times the weight of a person,then the maximum acceleration with which the person can safely climb up the rope is ($g$ = acceleration due to gravity).

The mass of a lift is $500\, kg$. When it ascends with an acceleration of $2\, m/s^2$,the tension in the cable will be........... $N$ $[g = 10\, m/s^2]$

For the given figure,the tension in the string $T_1$ is .......... $N$.

What will be the acceleration of the system and tension in the rope connecting $5\,kg$ and $1\,kg$ blocks?

$A$ rod of length $L$ and mass $M$ is acted on by two unequal forces $F_1$ and $F_2$ $(F_2 < F_1)$ as shown in the figure. The tension in the rod at a distance $y$ from the end $A$ is given by:

$A$ trolley of mass $5\,kg$ on a horizontal smooth surface is pulled by a load of mass $2\,kg$ by means of a uniform rope $ABC$ of length $2\,m$ and mass $1\,kg$. As the load falls from $BC = 0$ to $BC = 2\,m$,its acceleration in $m/s^2$ changes from: