If the circles $x^2+y^2+2hx+2ky=0$ and $x^2+y^2+2h'x+2k'y=0$ touch each other,then $\frac{h'k}{hk'} = $

  • A
    $0$
  • B
    $1$
  • C
    $2$
  • D
    $-1$

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