If the conductivity of $0.08 \ M$ $KCl$ solution is $2 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$,what is the molar conductivity of the solution?

Resistance of a conductivity cell filled with $0.1 \ mol \ L^{-1}$ $NaCl$ is $100 \ \Omega$. If the resistance of the same cell when filled with $0.02 \ mol \ L^{-1}$ $NaCl$ solution is $258 \ \Omega$,the conductivity of $0.02 \ mol \ L^{-1}$ $NaCl$ solution is (Conductivity of $0.1 \ mol \ L^{-1}$ $NaCl$ is $1.29 \ S \ m^{-1}$) (in $S \ m^{-1}$)

How is the cell constant determined?

Explain the measurement and calculation of the resistivity of an electrolytic solution.

The specific conductance $(k)$ of $0.02 \ M$ aqueous acetic acid solution at $298 \ K$ is $1.65 \times 10^{-4} \ S \ cm^{-1}$. The degree of dissociation $(\alpha)$ of acetic acid is: [Given: $\lambda_{H^{+}}^{\infty} = 349.1 \ S \ cm^2 \ mol^{-1}$ and $\lambda_{CH_3COO^{-}}^{\infty} = 40.9 \ S \ cm^2 \ mol^{-1}$]

What will be the concentration of $NaCl$ solution,if the molar conductivity and conductivity of $NaCl$ solution are $124.3 \ \Omega^{-1} \ cm^{2} \ mol^{-1}$ and $1.243 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$ respectively?