If the coordinates of the vertices of the triangle $ABC$ are $A(-1, 6)$,$B(-3, -9)$,and $C(5, -8)$,then the equation of the median through $C$ is

  • A
    $13x - 14y - 47 = 0$
  • B
    $13x - 14y + 47 = 0$
  • C
    $13x + 14y + 47 = 0$
  • D
    $13x + 14y - 47 = 0$

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