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(A) Given,the dielectric constant $K = \frac{4}{3}$.For a linear dielectric material,the relationship between the dielectric constant $K$ and the elec

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$\frac{\varepsilon_0}{3}$

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(A) Given,the dielectric constant $K = \frac{4}{3}$.For a linear dielectric material,the relationship between the dielectric constant $K$ and the electric susceptibility $\chi$ is given by $K = 1 + \chi_e$,where $\chi_e$ is the electric susceptibility (often denoted as $\chi$).Therefore,$\chi = K - 1$.Since the polarization $P$ is related to the electric field $E$ by $P = \chi \varepsilon_0 E$,the susceptibility in terms of $\varepsilon_0$ is expressed as $\chi = (K - 1) \varepsilon_0$.Substituting the given value of $K$:$\chi = \left( \frac{4}{3} - 1 \right) \varepsilon_0$$\chi = \left( \frac{4 - 3}{3} \right) \varepsilon_0$$\chi = \frac{\varepsilon_0}{3}$.

If the dielectric constant of a substance $K = \frac{4}{3}$,then the electric susceptibility $\chi$ in terms of vacuum permittivity $\varepsilon_0$ is

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