If the dipole moments of H_2S,NH_3,NF_3,and B | vedclass

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(A) The structure of a molecule is determined by its hybridization and the number of lone pairs on the central atom.$BF_3$ has $sp^2$ hybridization wi

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$BF_3$

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(A) The structure of a molecule is determined by its hybridization and the number of lone pairs on the central atom.$BF_3$ has $sp^2$ hybridization with no lone pairs on the boron atom,resulting in a trigonal planar geometry.$NH_3$ and $NF_3$ have $sp^3$ hybridization with one lone pair,resulting in a trigonal pyramidal geometry.$H_2S$ has $sp^3$ hybridization with two lone pairs,resulting in a bent ($V$-shaped) geometry.Since $BF_3$ is the only molecule with a trigonal planar structure,the correct option is $A$.

If the dipole moments of $H_2S$,$NH_3$,$NF_3$,and $BF_3$ are $0.95 \ D$,$1.47 \ D$,$0.23 \ D$,and $0.0 \ D$ respectively,the molecule that has a trigonal planar structure is:

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