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(C) Given equation: $y = A\sin PT + B\cos PT$Let $A = r\cos 	heta$ and $B = r\sin 	heta$,where $r = \sqrt{A^2 + B^2}$ and $	an 	heta = B/A$.Substi

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$A$ $S$.$H$.$M$.

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(C) Given equation: $y = A\sin PT + B\cos PT$Let $A = r\cos 	heta$ and $B = r\sin 	heta$,where $r = \sqrt{A^2 + B^2}$ and $	an 	heta = B/A$.Substituting these into the equation,we get:$y = r\cos 	heta \sin PT + r\sin 	heta \cos PT$Using the trigonometric identity $\sin(x + y) = \sin x \cos y + \cos x \sin y$,we have:$y = r\sin(PT + 	heta)$This is the standard form of the equation for Simple Harmonic Motion $(SHM)$,where $r$ is the amplitude,$P$ is the angular frequency,and $	heta$ is the phase constant.

If the displacement equation of a particle is represented by $y = A\sin PT + B\cos PT$,the particle executes

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