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(C) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_{0} \varepsilon_{r} A}{d}$.When the distance between

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Four times

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(C) The capacitance of a parallel plate capacitor is given by the formula $C = \frac{\varepsilon_{0} \varepsilon_{r} A}{d}$.When the distance between the plates is halved,the new distance $d' = \frac{d}{2}$.When the dielectric constant is doubled,the new dielectric constant $\varepsilon_{r}' = 2 \varepsilon_{r}$.The new capacitance $C'$ is given by:$C' = \frac{\varepsilon_{0} \varepsilon_{r}' A}{d'} = \frac{\varepsilon_{0} (2 \varepsilon_{r}) A}{d/2}$.Simplifying the expression:$C' = 4 	imes \frac{\varepsilon_{0} \varepsilon_{r} A}{d} = 4C$.Therefore,the capacitance becomes four times the original value.

If the distance between parallel plates of a capacitor is halved and the dielectric constant is doubled,then the capacitance will become:

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