If the energies of two photons are in the rat | vedclass

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is

Vedclass · Accepted Answer

$2:3$

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is the wavelength.Since $h$ and $c$ are constants,$E \propto \frac{1}{\lambda}$.Therefore,the ratio of energies is inversely proportional to the ratio of their wavelengths:$\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$Given $\frac{E_1}{E_2} = \frac{3}{2}$,we have $\frac{3}{2} = \frac{\lambda_2}{\lambda_1}$.Thus,the ratio of wavelengths $\lambda_1 : \lambda_2 = 2:3$.

If the energies of two photons are in the ratio of $3:2$,their wavelengths will be in the ratio of

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