If the equation of the curve which passes through the point $(1,1)$ satisfies the differential equation $\frac{dy}{dx} = \frac{2x-5y+3}{5x+2y-3}$, then the equation of that curve is:

  • A
    $x^2+5xy-y^2+3x-3y-5=0$
  • B
    $x^2+5xy-y^2+3x+3y-11=0$
  • C
    $x^2-5xy-y^2-3x-3y+11=0$
  • D
    $x^2-5xy-y^2+3x+3y-1=0$

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