If the events $A$ and $B$ are mutually exclusive,then $P\left( \frac{A}{B} \right) = $

  • A
    $0$
  • B
    $1$
  • C
    $\frac{P(A \cap B)}{P(A)}$
  • D
    $\frac{P(A \cap B)}{P(B)}$

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