If the foci of $\frac{x^{2}}{16}+\frac{y^{2}}{4}=1$ and $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{9}=1$ coincide,then the value of $a$ is

  • A
    $\sqrt{3}$
  • B
    $\frac{1}{\sqrt{3}}$
  • C
    $2$
  • D
    $1$

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