If the frequency of a tuning fork is 400 , Hz | vedclass

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(A) Given:Frequency $(f)$ = $400 \, Hz$Speed of sound $(V)$ = $340 \, m s^{-1}$Number of vibrations $(n)$ = $16$The time period $(T)$ for one vibratio

Vedclass · Accepted Answer

$13.6$

Vedclass · Answer

(A) Given:Frequency $(f)$ = $400 \, Hz$Speed of sound $(V)$ = $340 \, m s^{-1}$Number of vibrations $(n)$ = $16$The time period $(T)$ for one vibration is $T = 1/f = 1/400 \, s$.Total time $(t)$ taken for $16$ vibrations is $t = n 	imes T = 16 	imes (1/400) = 16/400 \, s$.Distance $(d)$ traveled by sound is calculated using the formula $d = V 	imes t$.Substituting the values: $d = 340 	imes (16/400) = 340 	imes 0.04 = 13.6 \, m$.Therefore,the sound travels $13.6 \, m$.

If the frequency of a tuning fork is $400 \, Hz$ and the speed of sound in air is $340 \, m s^{-1}$,find how far sound travels when the tuning fork makes $16$ vibrations. (in $, m$)

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