If the function given by $f(x) = \left(\frac{4x+1}{1-4x}\right)^{\frac{1}{x}}$ for $x \neq 0$ is continuous at $x = 0$,then the value of $f(0)$ is

  • A
    $e^{8}$
  • B
    $e^{10}$
  • C
    $e^{-8}$
  • D
    $e^{-10}$

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