If the ionisation energy for the hydrogen atom is $13.6 \ eV$,then the energy required to excite it from the ground state to the next higher state is nearly: (in $eV$)

Explain the formulas for the energy of an electron in an atom revolving around the nucleus in different orbits.

The ionisation potential of hydrogen atom is $13.6 \ V$. The energy required to remove an electron from the second orbit of hydrogen is......$eV$.

The total energy of an electron revolving in the second orbit of a hydrogen atom is

An electron with kinetic energy $E$ collides with a hydrogen atom in the ground state. The collision will be elastic

Energy of the electron in $n^{th}$ orbit of hydrogen atom is given by $E_n = - \frac{13.6}{n^2} \ eV$. The amount of energy needed to transfer an electron from the first orbit to the third orbit is........$eV$.