If the ionization constant of hypochlorous ac | vedclass

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(B) Given,ionization constant $(K_a) = 2.5 	imes 10^{-5}$ and molarity $(C) = 1.0 \ M$.For a weak acid,the degree of dissociation $(\alpha)$ is given

Vedclass · Accepted Answer

$2.3$

Vedclass · Answer

(B) Given,ionization constant $(K_a) = 2.5 	imes 10^{-5}$ and molarity $(C) = 1.0 \ M$.For a weak acid,the degree of dissociation $(\alpha)$ is given by $\alpha = \sqrt{\frac{K_a}{C}} = \sqrt{\frac{2.5 	imes 10^{-5}}{1}} = \sqrt{25 	imes 10^{-6}} = 5 	imes 10^{-3}$.The concentration of hydrogen ions $[H^{+}] = C 	imes \alpha = 1 	imes 5 	imes 10^{-3} = 5 	imes 10^{-3} \ M$.The $pH$ is calculated as:$pH = -\log[H^{+}] = -\log(5 	imes 10^{-3})$$pH = -(\log 5 + \log 10^{-3})$$pH = -(0.7 - 3) = -(-2.3) = 2.3$.

If the ionization constant of hypochlorous acid $(HOCl)$ is $2.5 \times 10^{-5}$,the $pH$ of $1.0 \ M$ of its solution is $(\log 5=0.7)$.

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