If the ionization potential of Li^{2+} is 122 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The ionization energy $(I.E.)$ for a hydrogen-like species is given by the formula: $I.E. = 13.6 	imes Z^{2} 	imes (\frac{1}{n_1^{2}} - \frac{1}

Vedclass · Accepted Answer

$489.6$

Vedclass · Answer

(C) The ionization energy $(I.E.)$ for a hydrogen-like species is given by the formula: $I.E. = 13.6 	imes Z^{2} 	imes (\frac{1}{n_1^{2}} - \frac{1}{n_2^{2}}) \ eV$. For ionization from ground state $(n=1)$ to infinity $(n=\infty)$,$I.E. = 13.6 	imes Z^{2} \ eV$. For $Li^{2+}$,$Z=3$,so $I.E. = 13.6 	imes 3^{2} = 13.6 	imes 9 = 122.4 \ eV$. For the $5^{th}$ ionization potential of Carbon $(Z=6)$,we are removing the $5^{th}$ electron from the $C^{4+}$ ion. The electronic configuration of $C^{4+}$ is $1s^{2}$. The $5^{th}$ electron is removed from the $n=1$ shell. $I.E._{5} = 13.6 	imes Z^{2} 	imes \frac{1}{n^{2}} = 13.6 	imes 6^{2} 	imes \frac{1}{1^{2}} = 13.6 	imes 36 = 489.6 \ eV$.

If the ionization potential of $Li^{2+}$ is $122.4 \ eV$,what is the $5^{th}$ ionization potential of carbon in $eV$?

Similar Questions

If the maximum kinetic energy of photoelectrons ejected from a metal surface when it is irradiated with a radiation of frequency $4 \times 10^{14} \ s^{-1}$ is $6.63 \times 10^{-20} \ J$,then the threshold frequency of the metal is

Calculate the radius of the first orbit of $Li^{2+}$. (in $pm$)

$(i)$ The energy associated with the first orbit in the hydrogen atom is $-2.18 \times 10^{-18} \, J \, atom^{-1}$. What is the energy associated with the fifth orbit?
$(ii)$ Calculate the radius of Bohr's fifth orbit for the hydrogen atom.

Which of the following electron transitions in a hydrogen atom will require the largest amount of energy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module