If the length of a DNA molecule is 1.1 metres | vedclass

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Question

(D) The distance between two consecutive base pairs in a $DNA$ molecule is $0.34 	ext{ nm}$ or $0.34 	imes 10^{-9} 	ext{ m}$.Given the total length

Vedclass · Accepted Answer

$3.3 	imes 10^{9} 	ext{ bp}$

Vedclass · Answer

(D) The distance between two consecutive base pairs in a $DNA$ molecule is $0.34 	ext{ nm}$ or $0.34 	imes 10^{-9} 	ext{ m}$.Given the total length of the $DNA$ molecule is $1.1 	ext{ m}$.The number of base pairs is calculated by dividing the total length by the distance between two consecutive base pairs:$	ext{Number of base pairs} = \frac{	ext{Total length}}{	ext{Distance between two base pairs}}$$	ext{Number of base pairs} = \frac{1.1 	ext{ m}}{0.34 	imes 10^{-9} 	ext{ m}}$$	ext{Number of base pairs} \approx 3.235 	imes 10^{9} 	ext{ bp}$.Rounding this to the nearest option,we get $3.3 	imes 10^{9} 	ext{ bp}$.

If the length of a $DNA$ molecule is $1.1$ metres,what will be the approximate number of base pairs?

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