(B) For a closed organ pipe of length $l$,the fundamental frequency (first note) is given by $n_1 = \frac{v}{4l}$.Given $v = 330 \ m/s$ and $l = 1 \ m

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(B) For a closed organ pipe of length $l$,the fundamental frequency (first note) is given by $n_1 = \frac{v}{4l}$.Given $v = 330 \ m/s$ and $l = 1 \ m$,we have $n_1 = \frac{330}{4 \times 1} = \frac{330}{4} \ Hz$.The frequencies of the notes in a closed pipe are given by odd harmonics: $n_k = (2k - 1)n_1$,where $k = 1, 2, 3, ...$.The first note is $n_1 = 1 \times n_1$.The second note (first overtone) is $n_2 = 3 \times n_1 = 3 \times \frac{330}{4} \ Hz$.

Class 11 Physics Waves and Sound Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

Easy

If the length of a closed organ pipe is $1 \ m$ and the velocity of sound is $330 \ m/s$,then the frequency for the second note (first overtone) is:

A
$4 \times \frac{330}{4} \ Hz$
B
$3 \times \frac{330}{4} \ Hz$
C
$2 \times \frac{330}{4} \ Hz$
D
$2 \times \frac{4}{330} \ Hz$

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Waves and Sound

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Longitudinal Stationary Waves (Organ Pipes) and Resonance Tube

Explain the formation of stationary waves in a closed pipe and derive the equations for natural frequencies (normal modes).

Difficult

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When an air column in a pipe open at both ends vibrates such that four antinodes and three nodes are formed,then the corresponding mode of vibration is

MediumMHT CET 2021

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In a resonance tube,the first resonance with a tuning fork occurs at $16 \ cm$ and the second at $49 \ cm$. If the velocity of sound is $330 \ m/s$,the frequency of the tuning fork is: (in $Hz$)

DifficultMHT CET 2011

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$A$ closed pipe of length $300 \,cm$ contains some sand. $A$ speaker is connected at one of its ends. The frequency of the speaker at which the sand will arrange itself in $20$ equidistant piles is close to .......... $kHz$ (velocity of sound is $300 \,m/s$).

DifficultKVPY 2017

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$A$ closed organ pipe and an open pipe of the same length produce $4$ beats when they are set into vibrations simultaneously. If the length of each of them were twice their initial lengths,the number of beats produced will be

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If the length of a closed organ pipe is $1 \ m$ and the velocity of sound is $330 \ m/s$,then the frequency for the second note (first overtone) is:

Similar Questions

Explain the formation of stationary waves in a closed pipe and derive the equations for natural frequencies (normal modes).

When an air column in a pipe open at both ends vibrates such that four antinodes and three nodes are formed,then the corresponding mode of vibration is

In a resonance tube,the first resonance with a tuning fork occurs at $16 \ cm$ and the second at $49 \ cm$. If the velocity of sound is $330 \ m/s$,the frequency of the tuning fork is: (in $Hz$)

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