If the linear speed of a particle moving in a | vedclass

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Question

(A) The relationship between linear speed $(v)$,angular speed $(\omega)$,and the radius of the circular path $(r)$ is given by the formula: $v = r\ome

Vedclass · Accepted Answer

$ 1/r $

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(A) The relationship between linear speed $(v)$,angular speed $(\omega)$,and the radius of the circular path $(r)$ is given by the formula: $v = r\omega$.Given that the linear speed $(v)$ is constant,we can rearrange the formula to solve for angular speed: $\omega = \frac{v}{r}$.Since $v$ is constant,it follows that $\omega \propto \frac{1}{r}$.Therefore,the angular speed is inversely proportional to the radius of the circle.

If the linear speed of a particle moving in a circular path is constant,then the angular speed is proportional to (where $r$ is the radius of the circle):

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