If the lines represented by the equation 6x^2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given equation of the pair of lines is $6x^2 + 41xy - 7y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 6$,$

Vedclass · Accepted Answer

$-6/7$

Vedclass · Answer

(A) The given equation of the pair of lines is $6x^2 + 41xy - 7y^2 = 0$.Comparing this with the general form $ax^2 + 2hxy + by^2 = 0$,we get $a = 6$,$2h = 41$,and $b = -7$.Let the slopes of the two lines be $m_1 = 	an \alpha$ and $m_2 = 	an \beta$.For a pair of lines $ax^2 + 2hxy + by^2 = 0$,the product of the slopes is given by $m_1 m_2 = \frac{a}{b}$.Substituting the values,we get $	an \alpha \cdot 	an \beta = \frac{6}{-7} = -\frac{6}{7}$.

If the lines represented by the equation $6x^2 + 41xy - 7y^2 = 0$ make angles $\alpha$ and $\beta$ with the $x$-axis,then $\tan \alpha \cdot \tan \beta = $

Similar Questions

The square of the difference of the slopes of the lines represented by the equation $x^2(\sec^2 \theta - \sin^2 \theta) - 2xy \tan \theta + y^2 \sin^2 \theta = 0$ is:

If one of the lines represented by the equation $ax^2 + 2hxy + by^2 = 0$ bisects the angle between the coordinate axes in the first quadrant,then which of the following is true?

The equation $8 x^2-24 x y+18 y^2-6 x+9 y-5=0$ represents a

If $P_1$ and $P_2$ are perpendicular distances (in units) from point $(2, -1)$ to the pair of lines $2x^2 - 5xy + 2y^2 = 0$,then the value of $P_1 P_2$ is

If $lx^2+3xy-2y^2-5x+5y+k=0$ represents a pair of perpendicular lines,then

Vedclass Test Series

Exam Paper Generator

Online Exam Module