If the magnitude of a vector overrightarrow{p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnitude of a vector $\overrightarrow{p}$ is given by the formula: $|\overrightarrow{p}| = \sqrt{p_x^2 + p_y^2}$.Given, $|\overrightarrow{p}|

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(A) The magnitude of a vector $\overrightarrow{p}$ is given by the formula: $|\overrightarrow{p}| = \sqrt{p_x^2 + p_y^2}$.Given, $|\overrightarrow{p}| = 25 	ext{ units}$ and $p_y = 7 	ext{ units}$.Substituting the values into the formula: $25 = \sqrt{p_x^2 + 7^2}$.Squaring both sides: $25^2 = p_x^2 + 7^2$.$625 = p_x^2 + 49$.$p_x^2 = 625 - 49 = 576$.Taking the square root: $p_x = \sqrt{576} = 24 	ext{ units}$.Therefore, the $x$-component is $24 	ext{ units}$.

If the magnitude of a vector $\overrightarrow{p}$ is $25 \text{ units}$ and its $y$-component is $7 \text{ units}$, then its $x$-component is (in $\text{ units}$)

Similar Questions

$A$ person pushes a box kept on a horizontal surface with a force of $100\,N$ as shown in the figure. In unit vector notation,the force $\vec{F}$ can be expressed as?

Which one of the following pairs cannot be the rectangular components of a force vector of $10 \, N$?

The component of a vector $\vec{r}$ along the $x$-axis will have a maximum value if

$A$ person walks $25.0^{\circ}$ north of east for $3.18 \,km$. How far would she have to walk due north and then due east to arrive at the same location?

Vector $P = 6 \hat{i} + 4 \sqrt{2} \hat{j} + 4 \sqrt{2} \hat{k}$ makes an angle with the $z$-axis equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module