If the measures of the sides of a triangle ar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) triangle is a right-angled triangle if the square of the longest side is equal to the sum of the squares of the other two sides (Pythagoras theore

Vedclass · Accepted Answer

$8, 24, 26$

Vedclass · Answer

(D) triangle is a right-angled triangle if the square of the longest side is equal to the sum of the squares of the other two sides (Pythagoras theorem: $a^2 + b^2 = c^2$).For option $A$: $3^2 + 4^2 = 9 + 16 = 25 = 5^2$. This is a right-angled triangle.For option $B$: $5^2 + 12^2 = 25 + 144 = 169 = 13^2$. This is a right-angled triangle.For option $C$: $7^2 + 24^2 = 49 + 576 = 625 = 25^2$. This is a right-angled triangle.For option $D$: $8^2 + 24^2 = 64 + 576 = 640$,while $26^2 = 676$. Since $640 
eq 676$,this is not a right-angled triangle.

If the measures of the sides of a triangle are $\ldots \ldots \ldots,$ then it is not a right-angled triangle.

Similar Questions

In $\Delta XYZ$,$m\angle Y = 90^{\circ}$. If $XY = a^{2} - b^{2}$ and $YZ = 2ab$,find $XZ$ (where $a > b > 0$).

In $\Delta ABC$,the bisector of $\angle A$ intersects $\overline{BC}$ at $D$. Prove that $BD = \frac{BC \times AB}{AB + AC}$ and $DC = \frac{BC \times AC}{AB + AC}$.

$\square XYZW$ is a rectangle. If $XY + YZ = 17$ and $XZ + YW = 26$,find $XY$ and $YZ$ (given $XY > YZ$).

In $\Delta PQR$,$Z$,$X$,and $Y$ are the midpoints of $\overline{PQ}$,$\overline{QR}$,and $\overline{PR}$ respectively. Prove that the correspondence $PQR \leftrightarrow XYZ$ is a similarity.

$\Delta ABC \sim \Delta PQR$ for the correspondence $ABC \leftrightarrow PQR$. If $AB = 3, BC = 4, AC = 5$ and $QR = 6$,find $PQ$ and $PR$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module