If the number 481*673 is completely divisible | vedclass

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(D) Let the missing digit in place of $*$ be $x$.For a number to be divisible by $9$,the sum of its digits must be divisible by $9$.The sum of the dig

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(D) Let the missing digit in place of $*$ be $x$.For a number to be divisible by $9$,the sum of its digits must be divisible by $9$.The sum of the digits of $481*673$ is $4 + 8 + 1 + x + 6 + 7 + 3 = 29 + x$.For $(29 + x)$ to be divisible by $9$,the next multiple of $9$ after $29$ is $36$.Therefore,$29 + x = 36$,which gives $x = 36 - 29 = 7$.Thus,the smallest whole number in place of $*$ is $7$.

If the number $481673$ is completely divisible by $9$,then the smallest whole number in place of $$ will be

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If the number $481*673$ is completely divisible by $9$,then the smallest whole number in place of $*$ will be