If the numbers appearing on the two throws of a fair six-faced die are $\alpha$ and $\beta$,then the probability that $x^{2}+\alpha x+\beta > 0$ for all $x \in R$ is:

  • A
    $\frac{17}{36}$
  • B
    $\frac{4}{9}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{19}{36}$

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