If the origin is shifted to remove the first degree terms from the equation $2x^2 - 3y^2 + 4xy + 4x + 4y - 14 = 0$,then with respect to this new coordinate system,the transformed equation of $x^2 + y^2 - 3xy + 4y + 3 = 0$ is

  • A
    $x^2 + y^2 - 3xy - 2x + y + 6 = 0$
  • B
    $x^2 + y^2 - 3xy - 2x + 7y + 3 = 0$
  • C
    $x^2 + y^2 - 3xy - 2x + y + 4 = 0$
  • D
    $x^2 + y^2 - 3xy - 2x + 7y + 4 = 0$

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