If the oxygen (O_2) has a root mean square ve | vedclass

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(C) The root mean square velocity $(v_{rms})$ of a gas is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas consta

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$4C \ m/s$

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(C) The root mean square velocity $(v_{rms})$ of a gas is given by the formula: $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.From this,we see that $v_{rms} \propto \frac{1}{\sqrt{M}}$.For oxygen $(O_2)$,$M_{O_2} = 32 \ g/mol$. For hydrogen $(H_2)$,$M_{H_2} = 2 \ g/mol$.Given $v_{O_2} = C$,we have the ratio: $\frac{v_{H_2}}{v_{O_2}} = \sqrt{\frac{M_{O_2}}{M_{H_2}}}$.Substituting the values: $\frac{v_{H_2}}{C} = \sqrt{\frac{32}{2}} = \sqrt{16} = 4$.Therefore,$v_{H_2} = 4C \ m/s$.

If the oxygen $(O_2)$ has a root mean square velocity of $C \ m/s$,then the root mean square velocity of hydrogen $(H_2)$ at the same temperature will be:

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