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(D) For an electromagnetic wave,the relationship between the peak electric field $(E_0)$ and the peak magnetic field $(B_0)$ is given by $E_0 = c B_0$

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$9$

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(D) For an electromagnetic wave,the relationship between the peak electric field $(E_0)$ and the peak magnetic field $(B_0)$ is given by $E_0 = c B_0$,where $c$ is the speed of light in vacuum.Given:$B_0 = 30 	imes 10^{-9} \ T$$c = 3 	imes 10^8 \ m/s$Substituting these values into the formula:$E_0 = (3 	imes 10^8 \ m/s) 	imes (30 	imes 10^{-9} \ T)$$E_0 = 90 	imes 10^{-1} \ Vm^{-1}$$E_0 = 9 \ Vm^{-1}$Therefore,the peak value of the electric field is $9 \ Vm^{-1}$.

If the peak value of the magnetic field of an electromagnetic wave is $30 \times 10^{-9} \ T$,then the peak value of the electric field is (in $Vm^{-1}$)

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