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(B) The cut-off wavelength (also known as the minimum wavelength) of $X$-rays produced in a Coolidge tube is given by the formula: $\lambda_{\min} = \

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Is halved

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(B) The cut-off wavelength (also known as the minimum wavelength) of $X$-rays produced in a Coolidge tube is given by the formula: $\lambda_{\min} = \frac{hc}{eV} = \frac{12400}{V} 	ext{ Å}$.From this relation, it is clear that $\lambda_{\min} \propto \frac{1}{V}$.If the potential difference $V$ is doubled (i.e., $V' = 2V$), the new cut-off wavelength $\lambda'_{\min}$ becomes:$\lambda'_{\min} = \frac{12400}{2V} = \frac{1}{2} \left( \frac{12400}{V} ight) = \frac{1}{2} \lambda_{\min}$.Therefore, the cut-off wavelength is halved.

If the potential difference $V$ applied to the Coolidge tube is doubled, then the cut-off wavelength

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