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(A) The root mean square $(RMS)$ speed of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas consta

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It will not change

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(A) The root mean square $(RMS)$ speed of gas molecules is given by the formula $v_{rms} = \sqrt{\frac{3RT}{M}}$,where $R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.From this formula,it is clear that $v_{rms}$ depends only on the temperature $T$ and the molar mass $M$ of the gas.Since the temperature $T$ is kept constant and the molar mass $M$ is a property of the gas,the $RMS$ speed remains unchanged even if the pressure is doubled.Therefore,the correct option is $A$.

If the pressure of a gas is doubled while keeping the temperature constant,what will happen to the root mean square $(RMS)$ speed of the gas molecules?

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