Difficult
If the principal quantum number $n=6,$ the correct sequence of filling of electrons will be
- A$ns \to (n-2)f \to np \to (n-1)d$
- B$ns \to (n-2)f \to (n-1)d \to np$
- C$ns \to np \to (n-1)d \to (n-2)f$
- D$ns \to (n-1)d \to (n-2)f \to np$
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Similar Questions
If $n$ and $l$ represent the principal and azimuthal quantum numbers respectively, the formula used to determine the number of radial nodes possible for a given orbital is:
Consider the following sets of quantum numbers. Which of the below settings is not a permissible arrangement of electrons in an atom?
The principal quantum number represents:
Easy
View SolutionConsider the hypothetical situation where the azimuthal quantum number,$l$,takes values $0, 1, 2, \ldots, n+1$,where $n$ is the principal quantum number. Then,the element with atomic number
DifficultJEE MAIN 2020
View Solution$A$ certain orbital has no angular nodes and two radial nodes. The orbital is
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