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(D) The rate of radioactive disintegration is given by the formula: $Rate = \lambda 	imes N$,where $\lambda$ is the decay constant and $N$ is the num

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Doubled

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(D) The rate of radioactive disintegration is given by the formula: $Rate = \lambda 	imes N$,where $\lambda$ is the decay constant and $N$ is the number of radioactive atoms present.Since the rate is directly proportional to the number of atoms $(Rate \propto N)$,if the quantity of the radioactive element is doubled,the number of atoms $N$ becomes $2N$.Therefore,the new rate becomes $\lambda 	imes (2N) = 2 	imes (\lambda 	imes N)$,which is double the original rate.Thus,the correct option is $(D)$.

If the quantity of a radioactive element is doubled,then its rate of disintegration per unit time will be

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