If the radius of a sphere is doubled,its volu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The volume $V$ of a sphere with radius $r$ is given by the formula $V = \frac{4}{3} \pi r^3$.If the radius is doubled,the new radius $r' = 2r$.The

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(B) The volume $V$ of a sphere with radius $r$ is given by the formula $V = \frac{4}{3} \pi r^3$.If the radius is doubled,the new radius $r' = 2r$.The new volume $V'$ is given by $V' = \frac{4}{3} \pi (r')^3$.Substituting $r' = 2r$ into the formula,we get $V' = \frac{4}{3} \pi (2r)^3 = \frac{4}{3} \pi (8r^3) = 8 	imes (\frac{4}{3} \pi r^3)$.Therefore,$V' = 8V$.Thus,the volume becomes $8$ times the original volume.

If the radius of a sphere is doubled,its volume becomes $\ldots \ldots \ldots \ldots$ times the original volume.

Similar Questions

If $x=-2$ is a solution of a quadratic equation $k x^{2}+5 x+2=0,$ then $k=\ldots \ldots \ldots \ldots$

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $4x^{2} + 12x + 9 = 0$.

Solve the following equation using the method of factorization and write its solution set: $x + 2 - \frac{6}{x + 2} = 1$

Find the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $4x^{2} + x - 3 = 0$

$A$ quadratic equation with integral coefficients must have integral roots. Justify your answer.

Vedclass Test Series

Exam Paper Generator

Online Exam Module