If the radius of the spherical Gaussian surface is increased,then the electric flux due to a point charge enclosed by the surface:

Consider three point charges $-2Q$, $Q$ and $-Q$ and three surfaces $S_1$, $S_2$ and $S_3$. Match the entries of List-$I$ with that of List-$II$ using Gauss's Law.

List-$I$	List-$II$
$(a)$ Net flux through $S_1$	$(i)$ $\frac{-2Q}{\epsilon_0}$
$(b)$ Net flux through $S_2$	(ii) $\frac{-Q}{\epsilon_0}$
$(c)$ Net flux through $S_3$	(iii) Zero

Four charges $2 \mu C, -3 \mu C, 4 \mu C, -4 \mu C$ and $-1 \mu C$ are enclosed by a Gaussian surface of radius $2 \ m$. The net outward flux through the Gaussian surface is (in $\mu V-m$):

$A$ point charge of $10^{-7} \text{ C}$ is situated at the centre of a cube of $1 \text{ m}$ side. The electric flux through its surface is

Give a reason: 'If the net flux associated with a closed surface is zero,then the net charge enclosed by that surface is zero.'

When a $10 \mu C$ charge is enclosed by a closed surface,the flux passing through the surface is $\phi$. Now,another $10 \mu C$ charge is placed inside the closed surface,then the flux passing through the surface is . . . . . . .