If the rate of disappearance of $N_2O_5$ in the following reaction is $1.2 \times 10^{-5} \ mol \ L^{-1} \ s^{-1}$,the rate of production of $NO_2$ in $mol \ L^{-1} \ s^{-1}$ is:
$2N_2O_{5(g)} \longrightarrow 4NO_{2(g)} + O_{2(g)}$

  • A
    $1.2 \times 10^{-5}$
  • B
    $3.6 \times 10^{-5}$
  • C
    $2.4 \times 10^{-5}$
  • D
    $4.8 \times 10^{-5}$

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