If the refractive index of water is frac{4}{3 | vedclass

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(A) The refractive index of glass with respect to water is given by the ratio of their absolute refractive indices (or refractive indices with respect

Vedclass · Accepted Answer

$\sin ^{-1}\left(\frac{4}{5}\right)$

Vedclass · Answer

(A) The refractive index of glass with respect to water is given by the ratio of their absolute refractive indices (or refractive indices with respect to air).Given: Refractive index of water,$\mu_w = \frac{4}{3}$.Refractive index of glass,$\mu_g = \frac{5}{3}$.The relative refractive index of glass with respect to water is $\mu = \frac{\mu_g}{\mu_w} = \frac{5/3}{4/3} = \frac{5}{4}$.The critical angle $C$ is defined by the relation $\sin C = \frac{1}{\mu}$.Substituting the value of $\mu$,we get $\sin C = \frac{1}{5/4} = \frac{4}{5}$.Therefore,the critical angle $C = \sin ^{-1}\left(\frac{4}{5}\right)$.

If the refractive index of water is $\frac{4}{3}$ and that of a given glass slab immersed in it is $\frac{5}{3}$,the value of the critical angle for a ray of light tending to go from glass to water is:

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