(C) Given the quadratic equation $3x^2 + 4kx + 3 = 0$. For the roots to be non-real,the discriminant $D$ must be less than $0$. $D = b^2 - 4ac < 0$ $(

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(C) Given the quadratic equation $3x^2 + 4kx + 3 = 0$. For the roots to be non-real,the discriminant $D$ must be less than $0$. $D = b^2 - 4ac $(4k)^2 - 4(3)(3) $16k^2 - 36 $16k^2 $k^2 $k^2 Taking the square root on both sides,we get $|k| Therefore,$-3/2 Thus,$k$ lies in the interval $(-3/2, 3/2)$.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Solution of quadratic equations and Nature of roots

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If the roots of the equation $3x^2 + 4kx + 3 = 0$ are non-real,then $k$ lies in the interval

AP EAMCET 2023 All AP EAMCET

A
$[-2, -3/2]$
B
$[3/2, 2]$
C
$(-3/2, 3/2)$
D
$(2, 3)$

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4-2.Quadratic Equations and Inequations

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Solution of quadratic equations and Nature of roots

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If the roots of the equation $3x^2 + 4kx + 3 = 0$ are non-real,then $k$ lies in the interval

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