If the side of a square is increased by 50 %, | vedclass

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Question

(C) Let the original side of the square be $x$. Then,the original area $= x^2$. If the side is increased by $50 \%$,the new side $= x + 0.5x = 1.5x$ o

Vedclass · Accepted Answer

$125$

Vedclass · Answer

(C) Let the original side of the square be $x$. Then,the original area $= x^2$. If the side is increased by $50 \%$,the new side $= x + 0.5x = 1.5x$ or $\frac{3x}{2}$. The new area $= (1.5x)^2 = 2.25x^2$ or $\frac{9x^2}{4}$. The increase in area $= 2.25x^2 - x^2 = 1.25x^2$. The percentage increase in area $= \frac{	ext{Increase in area}}{	ext{Original area}} 	imes 100 = \frac{1.25x^2}{x^2} 	imes 100 = 125 \%$.

If the side of a square is increased by $50 \%$,the percent increase in its area is: (in $\%$)

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