(C) Let the slopes of the two lines be $m$ and $2m$.From the equation $ax^2+2hxy+by^2=0$,we have:Sum of slopes: $m_1+m_2 = m+2m = 3m = -\frac{2h}{b} \

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(C) Let the slopes of the two lines be $m$ and $2m$.From the equation $ax^2+2hxy+by^2=0$,we have:Sum of slopes: $m_1+m_2 = m+2m = 3m = -\frac{2h}{b} \Rightarrow m = -\frac{2h}{3b}$.Product of slopes: $m_1 \times m_2 = m \times 2m = 2m^2 = \frac{a}{b}$.Substituting the value of $m$ into the product equation:$2(-\frac{2h}{3b})^2 = \frac{a}{b}$$2(\frac{4h^2}{9b^2}) = \frac{a}{b}$$\frac{8h^2}{9b^2} = \frac{a}{b}$$8h^2 = 9ab$.

Class 11 Mathematics Pair of straight lines Equation of pair of straight lines

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If the slope of one of the lines given by $ax^2+2hxy+by^2=0$ is two times the other,then

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$8h=9ab^2$
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$8h^2=9ab^2$
C
$8h^2=9ab$
D
$8h=9ab$

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If the slope of one of the lines given by $ax^2+2hxy+by^2=0$ is two times the other,then

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