If the solubility of $Ca_3(PO_4)_2$ in water is $x \ mol \ L^{-1}$, its solubility product in $mol^5 \ L^{-5}$ is (in $x^5$)

  • A
    $6$
  • B
    $36$
  • C
    $64$
  • D
    $108$

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